Question

Integrate completely with respect to x :
∫21(4x+6)dx
note 2 supperlative, 1 sub

12
6
8
16

Answer 1

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Answer on Question #46054 – Math - Integral Calculus

Task:

Integrate completely with respect to $x: \int_{1}^{2}(4x + 6)dx$

Solution:

By Newton-Leibnitz formula,

$$\int_{1}^{2}(4x + 6)dx = \left(\frac{4x^2}{2} + 6x\right)\bigg|_{1}^{2} = (2 \cdot 2^2 + 6 \cdot 2) - (2 + 6) = 8 + 12 - 8 = 12$$

Answer: 12