Question #46049

Integrate with respect to x :
∫10 xdx
4
1
2
12

Expert's answer

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Answer on Question #46049 – Math – Integral Calculus

Question:

Integrate with respect to xx :


10xdx\int 10\,x\,dx

Solution:

xndx=xn+1n+1+C,if n1\int x^n\,dx = \frac{x^{n+1}}{n+1} + C, \quad \text{if } n \neq -1


Then


10xdx=10x22+C=5x2+C,\int 10\,x\,dx = 10 \cdot \frac{x^2}{2} + C = 5 \cdot x^2 + C,


where CC is an arbitrary real constant.


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