Question #46046

Determine l= ∫2cosxdx
,given that l=7 when x=π2

3sinx+$
2sinx+5
4cosx+C
5sinx+C

Expert's answer

Answer on Question #46046 – Math – Integral Calculus

Determine l=2cosxdxl = \int 2\cos x \, dx , given that l=7l = 7 when x=2πx = 2\pi .

3sinx+$

2sinx+5

4cosx+C

5sinx+C

Solution


I=2cosxdx=2cosxdx=2sinx+cI(2π)=2sin(2π)+c=0+c=7I=2sinx+7\begin{array}{l} I = \int 2 \cos x \, dx = 2 \int \cos x \, dx = 2 \sin x + c \\ I(2\pi) = 2 \sin(2\pi) + c = 0 + c = 7 \Rightarrow I = 2 \sin x + 7 \\ \end{array}


Answer: I=2sinx+7I = 2\sin x + 7 , correct answers were absent.

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