Answer to Question #45972 in Integral Calculus for victor

Question #45972
Find
∫e2xdx
1
Expert's answer
2014-09-11T14:01:23-0400
∫e(2x)dx=(1/2)*∫e(2x)d(2x)=|substitution t=2x|=(1/2)*∫etdt=(1/2)*et+C=(1/2)*e2x+C, where C is an arbitrary real constant.

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