Answer on Question #45967 – Math - Integral Calculus
Find the integral with respect to
x:J(exx)(ex1)dx
Solution
∫x⋅ex⋅ex+1dx=e∫x⋅e2xdx=e∫x2d(e2x)=e(2xe2x−21∫e2xdx)=2e(xe2x−2e2x+C)=2e(xe2x−2e2x)+C0
In this task the next rule (integration by parts) were used :
∫u⋅dv=u⋅v−∫v⋅du
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