Answer to Question #45964 in Integral Calculus for victor

Question #45964

Integrate with respect to x :
∫3−1x7+x2−−−−−√dx

Expert's answer

∫(3−x⁷+x²−√x)dx=3∫dx-∫x⁷dx+∫x²dx-∫√xdx=3x-x⁸/8+x³/3-2(x^3/2)/3+C, where C is an arbitrary real constant.

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