Answer to Question #45964 in Integral Calculus for victor

Question #45964
Integrate with respect to x :
∫3−1x7+x2−−−−−√dx
1
Expert's answer
2014-09-11T13:45:40-0400
∫(3−x7+x2−√x)dx=3∫dx-∫x7dx+∫x2dx-∫√xdx=3x-x8/8+x3/3-2(x3/2)/3+C, where C is an arbitrary real constant.

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