Question #45955
Integrate with respect to x :
∫10(2x2−4x−6)
1
Expert's answer
2014-09-11T12:50:23-0400
∫10(2x2−4x−6)dx=10∫(2x2−4x−6)dx=10∫2x2dx-10∫4xdx-10∫6dx=20∫x2dx-40∫xdx-60∫dx=20x3/3-40x2/2-60x+C, where C is an arbitrary real constant.

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