Answer on Question #45745 – Math – Integral Calculus
Determine I=∫2exdx, given that I=50.2, when x=3.
Solution.
First of all we will find the indefinite integral:
I=∫2exdx=2∫exdx=2ex+C.
We know, that I=50.2, when x=3. Hence, we can use this condition to calculate the constant C:
50.2=2e3+C,C=50.2−2e3.e≈2.7183, then e3≈20.1. It we can find with help of calculator.
Now we can evaluate C:
C=50.2−2⋅20.1=50.2−40.2=10.
Answer:
hence, our indefinite integral I=2ex+50.2−2e3 (approximately I=2ex+10).
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