Question #45745

Determine l=
∫2exdx
,given that l=50.2 when x =3

Expert's answer

Answer on Question #45745 – Math – Integral Calculus

Determine I=2exdxI = \int 2e^{x}dx, given that I=50.2I = 50.2, when x=3x = 3.

Solution.

First of all we will find the indefinite integral:


I=2exdx=2exdx=2ex+C.I = \int 2e^{x}dx = 2\int e^{x}dx = 2e^{x} + C.


We know, that I=50.2I = 50.2, when x=3x = 3. Hence, we can use this condition to calculate the constant CC:


50.2=2e3+C,50.2 = 2e^{3} + C,C=50.22e3.C = 50.2 - 2e^{3}.

e2.7183e \approx 2.7183, then e320.1e^{3} \approx 20.1. It we can find with help of calculator.

Now we can evaluate CC:


C=50.2220.1=50.240.2=10.C = 50.2 - 2 \cdot 20.1 = 50.2 - 40.2 = 10.


Answer:

hence, our indefinite integral I=2ex+50.22e3I = 2e^{x} + 50.2 - 2e^{3} (approximately I=2ex+10I = 2e^{x} + 10).

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