Answer on Question #45744 – Math – Integral Calculus
Determine I=∫2cosx dxI = \int 2\cos x \, dxI=∫2cosxdx, given that I=7I = 7I=7 when x=2πx = 2\pix=2π.
Solution
Answer: I=2sinx+7I = 2 \sin x + 7I=2sinx+7
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