Question #45742

Determine l=
∫4x2dx
,given that l= 25when l=25 when x=3.

Expert's answer

Answer on Question #45742 – Math – Integral Calculus

Question.

Determine I=4x2dxI = \int 4x^{2}dx, given that I=25I = 25 when x=3x = 3.

Solution.


I=4x2dx=43x3+c. Let x=3. Then I=4333+c=36+c=25c=11. So I = \int 4x^{2}dx = \frac{4}{3}x^{3} + c. \text{ Let } x = 3. \text{ Then } I = \frac{4}{3}3^{3} + c = 36 + c = 25 \Rightarrow c = -11. \text{ So }I=43x311.I = \frac{4}{3}x^{3} - 11.


Answer. I=43x311I = \frac{4}{3}x^{3} - 11.

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