Question #41903

integral 2z/(z^2+1)^1/3 dz

Expert's answer

Answer on Question #41903 – Math – Integral Calculus:


2zdz(z2+1)13=d(z2+1)(z2+1)13=[z2+1=t]=t13dt=t2323+C=32(z2+1)23+C.\int \frac {2 z d z}{(z ^ {2} + 1) ^ {\frac {1}{3}}} = \int \frac {d (z ^ {2} + 1)}{(z ^ {2} + 1) ^ {\frac {1}{3}}} = [ z ^ {2} + 1 = t ] = \int t ^ {- \frac {1}{3}} d t = \frac {t ^ {\frac {2}{3}}}{\frac {2}{3}} + C = \frac {3}{2} (z ^ {2} + 1) ^ {\frac {2}{3}} + C.


www.AssignmentExpert.com


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS