Question #41417

Show that the functions f(x,y)= y/x and g(x,y)= (x-y)/(x+y) are functionally dependent .
Find a functional relation between them .

Expert's answer

Answer on Question #41417 – Math - Integral Calculus

We have two functions:


f(x,y)=yxandg(x,y)=xyx+yf(x, y) = \frac{y}{x} \quad \text{and} \quad g(x, y) = \frac{x - y}{x + y}


Consider the second function:


g(x,y)=xyx+yg(x, y) = \frac{x - y}{x + y}


Transform:


xyx+y=xyx+y1x1x=xyxx+yx=1yx1+yx\frac{x - y}{x + y} = \frac{x - y}{x + y} \cdot \frac{\frac{1}{x}}{\frac{1}{x}} = \frac{\frac{x - y}{x}}{\frac{x + y}{x}} = \frac{1 - \frac{y}{x}}{1 + \frac{y}{x}}


Then


g(x,y)=1yx1+yx=1f(x,y)1+f(x,y)g(x, y) = \frac{1 - \frac{y}{x}}{1 + \frac{y}{x}} = \frac{1 - f(x, y)}{1 + f(x, y)}


So we have a functional relation between f(x,y)f(x, y) and g(x,y)g(x, y):


g(x,y)=1f(x,y)1+f(x,y)g(x, y) = \frac{1 - f(x, y)}{1 + f(x, y)}


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