Answer on Question #41417 – Math - Integral Calculus
We have two functions:
f(x,y)=xyandg(x,y)=x+yx−y
Consider the second function:
g(x,y)=x+yx−y
Transform:
x+yx−y=x+yx−y⋅x1x1=xx+yxx−y=1+xy1−xy
Then
g(x,y)=1+xy1−xy=1+f(x,y)1−f(x,y)
So we have a functional relation between f(x,y) and g(x,y):
g(x,y)=1+f(x,y)1−f(x,y)
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