Question #32989

Find the integral of x cos ax^2 dx with respect to x

a. cos^3x + c

b. sin^2x + c

c. sec^2x + 1

d. 1/2 a sin ax^2 + c
1

Expert's answer

2013-07-22T10:17:15-0400

Find the integral of xcosax2dxx \cos ax^2 dx with respect to xx

a. cos3x+c\cos^3 x + c

b. sin2x+c\sin^2 x + c

c. sec2x+1\sec^2 x + 1

d. 12asinax2+c\frac{1}{2a} \sin ax^2 + c

**Solution.**

Let's integrate it:


xcosax2dx\int x \cos a x ^ {2} d x


Substitute ax2=ta x^{2} = t, then dt=2axdxdt = 2a x d x. We have


xcosax2dx=1a2cosax22axdx=12acostdt=12asint+c\int x \cos a x ^ {2} d x = \int \frac {1}{a ^ {2}} \cos a x ^ {2} \cdot 2 a x d x = \frac {1}{2 a} \int \cos t d t = \frac {1}{2 a} \sin t + c


Substitute back t=ax2t = a x^{2}:


12asint+c=12asinax2+c{\frac {1}{2 a}} \sin t + c = {\frac {1}{2 a}} \sin a x ^ {2} + c


**Answer:**

d. 12asinax2+c\frac{1}{2a} \sin ax^2 + c

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