Find the integral of xcosax2dx with respect to x
a. cos3x+c
b. sin2x+c
c. sec2x+1
d. 2a1sinax2+c
**Solution.**
Let's integrate it:
∫xcosax2dx
Substitute ax2=t, then dt=2axdx. We have
∫xcosax2dx=∫a21cosax2⋅2axdx=2a1∫costdt=2a1sint+c
Substitute back t=ax2:
2a1sint+c=2a1sinax2+c
**Answer:**
d. 2a1sinax2+c
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