Determine l=∫2cosπ2 dxl = \int 2\cos \frac{\pi}{2} \, dxl=∫2cos2πdx, given that l=7l = 7l=7, when x=90x = 90x=90
a) cosx+sinx+c\cos x + \sin x + ccosx+sinx+c
b) 2sinx+52\sin x + 52sinx+5
c) sinx+c\sin x + csinx+c
d) cscx+c\csc x + ccscx+c
**Solution**
But
So
Let's find "c"
and
Answer: b) 2sinx+52 \sin x + 52sinx+5.
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