Question #31057

Determine l = ∫ 2 cos⁡ x dx, given that l=7, when x=

cosx + sinx + c

2 sin x + 5

sin x + c

cosec x + c

Expert's answer

Determine l=2cosπ2dxl = \int 2\cos \frac{\pi}{2} \, dx, given that l=7l = 7, when x=90x = 90

a) cosx+sinx+c\cos x + \sin x + c

b) 2sinx+52\sin x + 5

c) sinx+c\sin x + c

d) cscx+c\csc x + c

**Solution**


I=2cosxdx=2cosxdxI = \int 2 \cos x \, dx = 2 \int \cos x \, dx


But


cosxdx=sinx+c\int \cos x \, dx = \sin x + c


So


I=2(sinx+c)I = 2 (\sin x + c)


Let's find "c"


I=7=2(sin90+c)=2(1+c)c=2.5I = 7 = 2 (\sin 90 + c) = 2 (1 + c) \rightarrow c = 2.5


and


I=2sinx+5I = 2 \sin x + 5


Answer: b) 2sinx+52 \sin x + 5.

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