Integrate with respect to x: ∫ x^6 dx
a. x^7/7+c
b. x^6/7+c
c. x^5/5+c
d. x^2/2+c
∫ x^6 dx
We know that for every n( n is not equal to 0) ∫ x^ndx=x^(n+1)/(n+1) + const
In our case n=6, therefore ∫ x^6 dx=x^(6+1)/(6+1) +const=x^7/7 +c
Thus, the right answer is a. x^7/7+c
Need a fast expert's response?
Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!