Question #23041

Find the integral of ∫(y-5) dy ∕ y^2 + 5y + 6
1

Expert's answer

2013-01-29T11:17:52-0500
y5y2+5y+6dy=\int \frac {y - 5}{y ^ {2} + 5 y + 6} d y = \dotsy5y2+5y+6=y5(y+2)(y+3)=Ay+2+By+3=(A+B)y+(3A+2B)(y+2)(y+3)\frac {y - 5}{y ^ {2} + 5 y + 6} = \frac {y - 5}{(y + 2) (y + 3)} = \frac {A}{y + 2} + \frac {B}{y + 3} = \frac {(A + B) y + (3 A + 2 B)}{(y + 2) (y + 3)}{A+B=13A+2B=5\left\{ \begin{array}{l} A + B = 1 \\ 3 A + 2 B = - 5 \end{array} \right.{2A+2B=23A+2B=5\left\{ \begin{array}{l} 2 A + 2 B = 2 \\ 3 A + 2 B = - 5 \end{array} \right.A=7- A = 7A=7,B=8A = - 7, B = 8y5y2+5y+6=7y+2+8y+3\frac {y - 5}{y ^ {2} + 5 y + 6} = \frac {- 7}{y + 2} + \frac {8}{y + 3}=(7y+2+8y+3)dy=7lny+2+8lny+3+C,C=const\ldots = \int \left(\frac {- 7}{y + 2} + \frac {8}{y + 3}\right) d y = - 7 \ln | y + 2 | + 8 \ln | y + 3 | + C, C = c o n s t

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