Let the size of angle B be 3x3x3x and that of angle A be 2x2x2x
So,
90+3x+2x=1805x=90x=1890+3x+2x=180\\5x=90\\x=1890+3x+2x=1805x=90x=18
Size of ∠ A=2x=36°Size of∠B=3x=54°Size\ of\ \angle\ A=2x=36\degree\\Size\ of \angle B=3x=54\degreeSize of ∠ A=2x=36°Size of∠B=3x=54°
In △ ABCtan(∠B)=ACBC=1.3763So,BC=AC1.3763=10.172In\ \triangle\ ABC\\\tan(\angle B)=\frac{AC}{BC}=1.3763\\So,\\BC=\frac{AC}{1.3763}=10.172In △ ABCtan(∠B)=BCAC=1.3763So,BC=1.3763AC=10.172
AB=AC2+BC2=17.305AB=\sqrt{AC^2+BC^2}=17.305AB=AC2+BC2=17.305
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