3x2+3y2−6x−8y−12=3x2−6x+3−3+3y2−8y+163−163−12==(3x−3)2+(y−43)2−613 (3x−3)2+(y−43)2=613This is circle3x^2+3y^2-6x-8y-12 = 3x^2 - 6x + 3 - 3 +3y^2 - 8y + \frac{16}{3} - \frac{16}{3} - 12 = \\ =(\sqrt{3}x-\sqrt{3})^2 + (\sqrt{y}- \frac{4}{\sqrt{3}})^2 - \frac{61}{3} \\ \\ \\ (\sqrt{3}x-\sqrt{3})^2 + (\sqrt{y}- \frac{4}{\sqrt{3}})^2 = \frac{61}{3} \\ This is circle3x2+3y2−6x−8y−12=3x2−6x+3−3+3y2−8y+316−316−12==(3x−3)2+(y−34)2−361 (3x−3)2+(y−34)2=361This is circle
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment