Question

Find the coordinates of point P along directed line segment AB with A(-4,8) and B(16,-2), so that the ratio of AP to PB is 3 to 2

Answer 1

Answer on Question #81360 – Math – Geometry

Question

Find the coordinates of point P along directed line segment AB with A(-4,8) and B (16,-2), so that the ratio of AP to PB is 3 to 2.

Solution

$$P_x = A_x + (B_x - A_x) \cdot \frac{3}{5}$$ $$P_y = B_y + (A_y - B_y) \cdot \frac{2}{5}$$ $$P_x = -4 + (16 - (-4)) \cdot \frac{3}{5} = 8$$ $$P_y = -2 + (8 - (-2)) \cdot \frac{2}{5} = 2$$

Answer: $P(8; 2)$

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