Question #80656

A rectangle is placed around a semicircle as shown below. The length of the rectangle is 4mm
. Find the area of the shaded region.

Expert's answer

Answer on Question #80656 – Math – Geometry

Question

A rectangle is placed around a semicircle as shown below. The length of the rectangle is 4mm. Find the area of the shaded region.

Given:

The length of the rectangle: a=4mma = 4\,\mathrm{mm}

Solution

The area of the shaded area is equal to the difference between the areas of the rectangle and the semicircle inscribed in it:


S=SRectSSemicircleS = S_{\text{Rect}} - S_{\text{Semicircle}}


semicircle area:


SSemicircle=πd28S_{\text{Semicircle}} = \frac{\pi d^2}{8}


length:


a=d;a = d;


width:


b=d2;b = \frac{d}{2};


Area of the rectangle:


SRect=ab;S_{\text{Rect}} = a b;SRect=d22S_{\text{Rect}} = \frac{d^2}{2}S=d22πd28=d28(4π)=1.72mm2S = \frac{d^2}{2} - \frac{\pi d^2}{8} = \frac{d^2}{8} (4 - \pi) = 1.72\,\mathrm{mm}^2


Answer:

area of the shaded region: 1.72mm21.72\,\mathrm{mm}^2

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