Question #77265

Q. Calculate the first fundamental forms of the following surfaces:
1) σ(u,v) =(sinhusinhv, sinhv, sinhucoshv, sinhu)
2) σ(u,v)=(u-v,u+v,u^2+v^2)

Expert's answer

Answer on Question #77265, Math / Geometry


σ(u,v)=(sinhusinhv,sinhv,sinhucoshv,sinhu)\sigma(u, v) = (\sinh u \cdot \sinh v, \sinh v, \sinh u \cdot \cosh v, \sinh u)σu=(coshusinhv,0,coshucoshv,coshu)\frac{\partial \sigma}{\partial u} = (\cosh u \cdot \sinh v, 0, \cosh u \cdot \cosh v, \cosh u)σv=(sinhucoshv,coshv,sinhusinhv,0)\frac{\partial \sigma}{\partial v} = (\sinh u \cdot \cosh v, \cosh v, \sinh u \cdot \sinh v, 0)E=cosh2usinh2v+cosh2ucosh2v+cosh2u=2cosh2ucosh2vE = \cosh^2 u \cdot \sinh^2 v + \cosh^2 u \cdot \cosh^2 v + \cosh^2 u = 2 \cosh^2 u \cdot \cosh^2 vF=2sinhucoshusinhvcoshvF = 2 \sinh u \cdot \cosh u \cdot \sinh v \cdot \cosh vG=sinh2ucosh2v+cosh2v+sinh2usinh2vG = \sinh^2 u \cdot \cosh^2 v + \cosh^2 v + \sinh^2 u \cdot \sinh^2 v


Then, 1(x,y)=Ex2+2Fxy+Gy21(x,y) = Ex^2 + 2Fxy + Gy^2

σ(u,v)=(uv,u+v,u2+v2)\sigma(u, v) = (u - v, u + v, u^2 + v^2)σu=(1,1,2u)\frac{\partial \sigma}{\partial u} = (1, 1, 2u)σv=(1,1,2v)\frac{\partial \sigma}{\partial v} = (-1, 1, 2v)E=2+4u2E = 2 + 4u^2F=4uvF = 4uvG=2+4v2G = 2 + 4v^2


Then, 1(x,y)=Ex2+2Fxy+Gy21(x,y) = Ex^2 + 2Fxy + Gy^2

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