Question #65901

For what value of x will the angle between the lines with direction ratios (x, 2, 4) and
(1, 0, 1) be o 45 ?

Expert's answer

Answer on Question #65901 – Math – Geometry

Question

For what value of xx will the angle between the lines with direction ratios (x,2,4)(x, 2, 4) and (1,0,1)(1, 0, 1) be 4545{}^\circ?

Solution

Denote a=(a1,a2,a3)=(x,2,4)a = (a_1, a_2, a_3) = (x, 2, 4), b=(b1,b2,b3)=(1,0,1)b = (b_1, b_2, b_3) = (1, 0, 1).

According to the algebraic definition of the dot product (see [1], p.4)


ab=a1b1+a2b1+a3b3.a b = a_1 b_1 + a_2 b_1 + a_3 b_3.


The angle between vectors a,ba, b is defined by (see [1], p.6)


cos45=abab.\cos 45{}^\circ = \frac{a \cdot b}{||a|| \cdot ||b||}.


Using that cos45=2/2\cos 45{}^\circ = \sqrt{2}/2 and the previous formulas, we get


a1b1+a2b1+a3b3=abcos45,a_1 b_1 + a_2 b_1 + a_3 b_3 = ||a|| \cdot ||b|| \cdot \cos 45{}^\circ,x1+20+41=x2+4+161+122,x \cdot 1 + 2 \cdot 0 + 4 \cdot 1 = \sqrt{x^2 + 4 + 16} \cdot \sqrt{1 + 1} \cdot \frac{\sqrt{2}}{2},x+4=x2+20,x + 4 = \sqrt{x^2 + 20},(x+4)2=(x2+20)2,(x + 4)^2 = \left(\sqrt{x^2 + 20}\right)^2,x2+8x+16=x2+20,x^2 + 8x + 16 = x^2 + 20,8x=2016,8x = 20 - 16,8x=4,8x = 4,x=48,x = \frac{4}{8},x=12.x = \frac{1}{2}.


Answer: x=12x = \frac{1}{2}.

References:

[1] S. Lipschutz; M. Lipson (2009). Linear Algebra (Schaum’s Outlines) (4th ed.). McGraw Hill. ISBN 978-0-07-154352-1.

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