Question #65445
If you increase the dimensions of a square pyramid by 6 times, how much larger will the new surface area be?
Expert's answer
S=S_base+S_side
S_base=a^2
S_side=4(1/2 a×h)
h=√(a^2-a^2/4)
S=36+36√3=36(1+√3)
S_base=a^2
S_side=4(1/2 a×h)
h=√(a^2-a^2/4)
S=36+36√3=36(1+√3)
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