Question #61612

A classroom is 38 ft long, 24 ft wide and 10ft high. Determine the volume and surface area.

Expert's answer

Answer on Question #61612 – Math – Geometry

Question

A classroom is 38 ft long, 24 ft wide and 10 ft high. Determine the volume and surface area.

Solution

The classroom is right parallelepiped.


Volume=lwh\text{Volume} = l \cdot w \cdot h


The surface area of the parallelepiped is the sum of all areas of faces, which are rectangles.


Surface Area=2lw+2lh+2wh\text{Surface Area} = 2l \cdot w + 2l \cdot h + 2w \cdot hl=38ft,w=24ft,h=10ft.l = 38 \, \text{ft}, \quad w = 24 \, \text{ft}, \quad h = 10 \, \text{ft}.V=382410=9120(ft3)V = 38 \cdot 24 \cdot 10 = 9120 \, (\text{ft}^3)S=23824+23810+22410=3064(ft2).S = 2 \cdot 38 \cdot 24 + 2 \cdot 38 \cdot 10 + 2 \cdot 24 \cdot 10 = 3064 \, (\text{ft}^2).


Answer: 9120ft39120 \, \text{ft}^3, 3064ft23064 \, \text{ft}^2.

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