Answer to Question #61482 in Geometry for isa

Question

7 Evaluate
∫2−1y2+y−2dy
∫−12y2+y−2dy

716
716

316
316

1716
1716

516
516
8 Integrate with respect to x :
∫2−1x2(x3+4)2dx
∫−12x2(x3+4)2dx
12

12
12
6

512
512

Answer 1

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