Question

A tank, open at the top is made of sheet iron 1 in. thick. The internal dimensions of the tank are 4 ft., 8 in. long; 3 ft. wide 6 in. wide; 4 ft. 4 in. deep. Find the weight of the tank when empty, and find the weight when full of salt water.

Answer 1

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Answer on Question #57995 – Math – Geometry

Question

A tank, open at the top is made of sheet iron 1 in. thick. The internal dimensions of the tank are 4 ft., 8 in. long; 3 ft. wide 6 in. wide; 4 ft. 4 in. deep. Find the weight of the tank when empty, and find the weight when full of salt water.

Solution

Sides:

4 ft. 8 in. = 4,67;

3 ft. 6 in. = 3,5;

4 ft. 4 in. = 4,33.

Density of steel is 506 lb/ft³.

Let's find volumes of each side.

Bottom: 4 ft. 8 in. * 3 ft. 6 in. * 1 in. = 1,63 ft.;

2 opposite sides: 3 ft. 6 in. * 4 ft. 4 in. * 1 in. = 1,516 ft.;

2 another opposite sides: 4 ft. 8 in. * 4 ft. 4 in. * 1 in. = 2,022 ft.

So, weight of tank when it is empty is (1,63 + 1,516 + 2,022) * 506 = 2 615,0 lb.

Density of seawater is 64 lb/ft³.

Volume of tank is 4 ft. 8 in. * 3 ft. 6 in. * 4 ft. 4 in. = 70,77 m³.

So, weight of tank when it is full of salt water is

2 615,0 + 70,77 * 64 = 2 615,0 + 4 529,28 = 7 144,28 lb.