Question #57221

1. The radius of a regular decagon is 6m. What is the length of its apothem?
2. The area of a triangle with sides of length 10 in. and 17 in. and an included angle of 113° is equal to the area of a regular heptagon. Determine the length of each side of the heptagon.
3. Determine the area of the waste material in cutting out the largest circle (diameter is 23 cm) from a regular decagon.

Expert's answer

Answer on Question #57221 – Math – Geometry

1. The radius of a regular decagon is 6m6\mathrm{m}. What is the length of its apothem?

Solution

Definition: Apothem is a line segment from the center of a regular polygon to the midpoint of a side.

If you know the radius (distance from the center to a vertex), then the length of apothem is given by


apothem=rcos(180n),apothem = r \cos \left(\frac {180}{n}\right),


where

rr is the radius of the polygon,

nn is the number of sides,

cos\cos is the cosine function calculated in degrees.


apothem=6cos18010=6cos18=5.71m.apothem = 6 \cos \frac {180}{10} = 6 \cos 18 = 5.71\,\mathrm{m}.


Answer: 5.71m5.71\,\mathrm{m}.

2. The area of a triangle with sides of length 10 in. and 17 in. and an included angle of 113113{}^\circ is equal to the area of a regular heptagon. Determine the length of each side of the heptagon.

Solution

Atriangle=121017sin113=75.74A_{\text{triangle}} = \frac{1}{2} 10 \cdot 17 \sin 113{}^\circ = 75.74


By definition, all sides of a regular polygon are equal in length.

If you know the length of one of the sides, then the area is given by the formula:


area=s2N4tan(180N)area = \frac{s^2 N}{4 \tan \left(\frac{180}{N}\right)}


where ss is the length of any side,

NN is the number of sides,

tan\tan is the tangent function calculated in degrees.

Given the area of a regular heptagon is


Aheptagon=Atriangle=75.74.A_{\text{heptagon}} = A_{\text{triangle}} = 75.74.


On the other hand, by the formula (1)


Aheptagon=7s24tan(1807)s=47Aheptagontan(1807)=4775.740.48=20.77in.A_{\text{heptagon}} = \frac{7s^2}{4 \tan \left(\frac{180}{7}\right)} \Rightarrow s = \sqrt{\frac{4}{7} A_{\text{heptagon}} \tan \left(\frac{180}{7}\right)} = \sqrt{\frac{4}{7} \cdot 75.74 \cdot 0.48} = 20.77\,\mathrm{in}.

s=20.77ins = 20.77\,\mathrm{in}, where ss is the length of each side of the heptagon.

Answer: 20.77 in.

3. Determine the area of the waste material in cutting out the largest circle (diameter is 23 cm) from a regular decagon.

Solution

The area of the waste material is


Awaste material=AdecagonAcircleA_{\text{waste material}} = A_{\text{decagon}} - A_{\text{circle}}


The area of the circle is


Acircle=(232)2π=415.27A_{\text{circle}} = \left(\frac{23}{2}\right)^2 \pi = 415.27


If you know the apothem, or inradius, then the area of a regular polygon is given by


area=A2Ntan(180N)\text{area} = A^2 N \tan \left(\frac{180}{N}\right)


where

AA is the length of the apothem (inradius),

NN is the number of sides,

tan\tan is the tangent function calculated in degrees.

The area of the regular decagon is


Adecagon=(232)210tan18=429.71A_{\text{decagon}} = \left(\frac{23}{2}\right)^2 \cdot 10 \cdot \tan 18 = 429.71


Then


Awaste material=429.71415.27=14.44cm2.A_{\text{waste material}} = 429.71 - 415.27 = 14.44 \, \text{cm}^2.


Answer: 14.44cm214.44 \, \text{cm}^2.

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