Question #5526

A party planner is designing a conical canvas tent for a child's birthday party. The tent has no floor, and it has a radius of 3 ft, a perpendicular height of 4 ft, and a slant height of 5 ft. If canvas sells by the square yard only, for $23.00/yd2, how much will the material cost?

Expert's answer

A party planner is designing a conical canvas tent for a child's birthday party. The tent has no floor, and it has a radius of 3 ft, a perpendicular height of 4 ft, and a slant height of 5 ft. If canvas sells by the square yard only, for $23.00/yd², how much will the material cost?



Solution

We are given


r=3ftr = 3 \, \text{ft}l=5ftl = 5 \, \text{ft}h=4fth = 4 \, \text{ft}


According to Wikipedia http://en.wikipedia.org/wiki/Cone_(geometry)#Surface_Area

The lateral surface of a cone is:


SA=πrlSA = \pi r l


Calculating


SA=3.1435=47.1ft2SA = 3.14 * 3 * 5 = 47.1 \, \text{ft}^2


So we need 47.1 ft² of material to make the conical tent without floor.

Converting ft² into yd²


1yd=3feet1 \, \text{yd} = 3 \, \text{feet}1feet=13yd1 \, \text{feet} = \frac{1}{3} \, \text{yd}1ft2=19yd21 \, \text{ft}^2 = \frac{1}{9} \, \text{yd}^2


Thus:


SA=47.1ft2=47.19yd2=5.233yd2SA = 47.1 \, \text{ft}^2 = \frac{47.1}{9} \, \text{yd}^2 = 5.233 \, \text{yd}^2


As canvas sells by the square yard only we should by 6 yd² of it.

It will cost:


623=$1386 * 23 = \$138


Answer:


$138\$138

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