Question #5524
BestDrinks manufactures aluminum cans of pop in two sizes. Can A has a diameter of 2.5 inches and a height of 5 inches.
Can B has a diameter of 3 inches and a height of 4 inches. Which can requires more aluminum to manufacture?
Can B has a diameter of 3 inches and a height of 4 inches. Which can requires more aluminum to manufacture?
Expert's answer
The surface area of a can is
S = 2*pi*R^2 + 2*pi*R*H.
S1 = 2*pi*(2.5/2)^2 + 2*pi*(2.5/2)*5 ≈ 49.0874 square inches;
S2 = 2*pi*(3/2)^2 + 2*pi*(3/2)*4 ≈ 51.8363 square inches.
S1<S2, so the second can need more aluminum to manufacture.
S = 2*pi*R^2 + 2*pi*R*H.
S1 = 2*pi*(2.5/2)^2 + 2*pi*(2.5/2)*5 ≈ 49.0874 square inches;
S2 = 2*pi*(3/2)^2 + 2*pi*(3/2)*4 ≈ 51.8363 square inches.
S1<S2, so the second can need more aluminum to manufacture.
