Question #54831

Find the perimeter of the figure. https://ka-perseus-graphie.s3.amazonaws.com/eb8635a8059b2c69ad19bf8d44f5a7a7885cf622.png

Expert's answer

Answer on Question #54831 - Math - Geometry

Find the perimeter of the figure.



Solution

The figure consists of two squares and two quarters of circle. The perimeter equals P=AB+BM+MN+NK+KD+DAP = AB + \vec{BM} + MN + NK + \vec{KD} + DA .

It is given that AB=MN=NK=AD=4AB = MN = NK = AD = 4

Arcs BM,KD\vec{BM},\vec{KD} are equal, because they have the same radius R=4R = 4 ( R=MC=CKR = MC = CK ) and subtend equal angles 9090{}^{\circ} .

So BM=KD=142πR=πR2=2π\vec{BM} = \vec{KD} = \frac{1}{4} * 2\pi R = \frac{\pi R}{2} = 2\pi .

Finally P=4+2π+4+4+2π+4=16+4πP = 4 + 2\pi + 4 + 4 + 2\pi + 4 = 16 + 4\pi

Answer: P=16+4πP = 16 + 4\pi

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