Question #50570

Graph (0,8) (6,5) (-3,2) and find the area

Expert's answer

Answer on Question #50570 – Math – Geometry

Graph (0,8) (6,5) (-3,2) and find the area.



Solution.


S=p(pa)(pb)(pc);S = \sqrt {p (p - a) (p - b) (p - c)};p=a+b+c2;p = \frac {a + b + c}{2};a=(60)2+(58)2=45;a = \sqrt {(6 - 0) ^ {2} + (5 - 8) ^ {2}} = \sqrt {4 5};b=(36)2+(25)2=90;b = \sqrt {(- 3 - 6) ^ {2} + (2 - 5) ^ {2}} = \sqrt {9 0};c=(0(3))2+(82)2=45;c = \sqrt {(0 - (- 3)) ^ {2} + (8 - 2) ^ {2}} = \sqrt {4 5};p=45+90+452=245+902;p = \frac {\sqrt {4 5} + \sqrt {9 0} + \sqrt {4 5}}{2} = \frac {2 \sqrt {4 5} + \sqrt {9 0}}{2};S=245+902(245+90245)(245+90290)(245+90245)=S = \sqrt {\frac {2 \sqrt {4 5} + \sqrt {9 0}}{2} \left(\frac {2 \sqrt {4 5} + \sqrt {9 0}}{2} - \sqrt {4 5}\right) \left(\frac {2 \sqrt {4 5} + \sqrt {9 0}}{2} - \sqrt {9 0}\right) \left(\frac {2 \sqrt {4 5} + \sqrt {9 0}}{2} - \sqrt {4 5}\right)} =245+902245+902452245+902902245+902452=\sqrt {\frac {2 \sqrt {4 5} + \sqrt {9 0}}{2} \cdot \frac {2 \sqrt {4 5} + \sqrt {9 0} - 2 \sqrt {4 5}}{2} \cdot \frac {2 \sqrt {4 5} + \sqrt {9 0} - 2 \sqrt {9 0}}{2} \cdot \frac {2 \sqrt {4 5} + \sqrt {9 0} - 2 \sqrt {4 5}}{2}} =245+902902245902902=(90)222(245)2(90)222=904180904=904=22.5.\sqrt {\frac {2 \sqrt {4 5} + \sqrt {9 0}}{2} \cdot \frac {\sqrt {9 0}}{2} \cdot \frac {2 \sqrt {4 5} - \sqrt {9 0}}{2} \cdot \frac {\sqrt {9 0}}{2}} = \sqrt {\frac {(\sqrt {9 0}) ^ {2}}{2 ^ {2}} \cdot \frac {(2 \sqrt {4 5}) ^ {2} - (\sqrt {9 0}) ^ {2}}{2 ^ {2}}} = \sqrt {\frac {9 0}{4} \cdot \frac {1 8 0 - 9 0}{4}} = \frac {9 0}{4} = 2 2. 5.


Answer: 22.5.

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