Question #47534

How to prove the volume formula of con is 1/3×π×r^2×h;without using integration?

Expert's answer

Answer on Question #47534 – Math – Geometry

How to prove the volume formula of con is 1/3×π×r2×h1/3 \times \pi \times r^2 \times h; without using integration?

Solution.

Suppose we take a slice of the pyramid with the cone inside, from some way up the pyramid. This will look like a square with a circle fitting inside. Radius of the cone at this point, will be xx.

The area of the circle is πx2\pi x^2

The area of the square is 2x×2x=4x22x \times 2x = 4x^2

The ratio of the circle to the square is π4\frac{\pi}{4}.

The same is true for every slice we take: the area of the circle is π4\frac{\pi}{4} of the area of the square.

So, the volume of the cone will be π4\frac{\pi}{4} the volume of the pyramid.

The pyramid's volume is 4r2h3\frac{4r^2h}{3}.

So the cone's volume is 4r2h3π4=πr2h3\frac{4r^2h}{3} * \frac{\pi}{4} = \frac{\pi r^2h}{3}.

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