Question

Find the distance between the points to the nearest tenth. L(-4,11),M(-3,4)

Answer 1

Answer on Question #46961 – Math – Analytic Geometry

Question:

Find the distance between the points to the nearest tenth.

$$L(-4, 11), \quad M(-3, 4)$$

Solution.

Recall the formula for determining distance between two points $P_{1}(x_{1},y_{1})$ and $P_{2}(x_{2},y_{2})$:

$$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}.$$

In our case, $x_{1} = -4, y_{1} = 11, x_{2} = -3, y_{2} = 4$. Thus,

$$d = \sqrt{\left(-3 - (-4)\right)^{2} + (4 - 11)^{2}} = \sqrt{1^{2} + 7^{2}} = \sqrt{1 + 49} = \sqrt{50} \approx 7.071068 \approx 7.1.$$

Answer. The distance between points $L(-4, 11)$ and $M(-3, 4)$ is approximately equal to 7.1.

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