Answer on Question #42443 – Math - Geometry
Determine whether a triangle can be formed with the given side lengths. If so, use Heron's formula to find the area of the triangle.
a = 240
b = 127
c = 281
Help me please
Solution:
If the sum of the other 2 sides (without longest side) is not longer than the longest side then it can not form a triangle:
a + b > c ; 240 + 127 > 281 367 > 281 \begin{array}{l}
a + b > c; \\
240 + 127 > 281 \\
367 > 281 \\
\end{array} a + b > c ; 240 + 127 > 281 367 > 281
Hence, lengths a a a , b b b and c c c can form a triangle.
Heron's formula to find the area of the triangle. ( s = a + b + c 2 = 240 + 127 + 281 2 = 324 − half of the triangles perimeter ) \left(s = \frac{a + b + c}{2} = \frac{240 + 127 + 281}{2} = 324 - \text{half of the triangles perimeter}\right) ( s = 2 a + b + c = 2 240 + 127 + 281 = 324 − half of the triangles perimeter ) :
A = s ( s − a ) ( s − b ) ( s − c ) 15183.8 = 324 ⋅ ( 324 − 240 ) ( 324 − 127 ) ( 324 − 281 ) 15183.8 = 15183.8 A = \sqrt{\frac{s(s - a)(s - b)(s - c)}{15183.8}} = \sqrt{\frac{324 \cdot (324 - 240)(324 - 127)(324 - 281)}{15183.8}} = 15183.8 A = 15183.8 s ( s − a ) ( s − b ) ( s − c ) = 15183.8 324 ⋅ ( 324 − 240 ) ( 324 − 127 ) ( 324 − 281 ) = 15183.8
Answer: lengths a a a , b b b and c c c can form a triangle, area of the triangle is equal to 15183.8
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