Question #42394

Find all solutions to the equation.

7 sin^2x - 14 sin x + 2 = -5

How can I solve this please

Expert's answer

Answer on Question #42394 - Math - Geometry

Find all solutions to the equation


7sin2x14sinx+2=5.7 \sin^ {2} x - 14 \sin x + 2 = -5.


Solution. First, let us bring all the terms to the right-hand side of the equation:


7sin2x14sinx+7=07 \sin^ {2} x - 14 \sin x + 7 = 0


and divide by 7:


sin2x2sinx+1=0.\sin^ {2} x - 2 \sin x + 1 = 0.


This can be written as


(sinx1)2=0,(\sin x - 1) ^ {2} = 0,


or


sinx1=0,\sin x - 1 = 0,sinx=1.\sin x = 1.


Thus,


x=arcsin1+2πn,nZ,x = \arcsin 1 + 2\pi n, \quad n \in \mathbb{Z},


and finally


x=π2+2πn,nZ.x = \frac {\pi}{2} + 2 \pi n, \qquad n \in \mathbb {Z}.


Answer. x=π2+2πnx = \frac{\pi}{2} + 2\pi n for any nZn \in \mathbb{Z}.

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