Question

a packing box 2.2 ft by 4.9 ft by 5.5 ft is to be completely covered with tin. how many square feet of the metal are needed? (neglect waste for seams, etc.)

Answer 1

Answer on question 39999- Math – Geometry

ABCD = KLMN;

ABLK = DCMN;

ADNK = BLMC;

AB = 2,2;

BC = 4,9;

BL = 5,5;

S(ABCD) = 2,2 * 4,9 = 10,78 (sq ft)

S(ABLK) = 2,2 * 5,5 = 12,1 (sq ft)

S(ADNK) = 4,9 * 5,5 = 26,95 (sq ft)

S(necessary metal) = 10,78 * 2 + 12,1 * 2 + 26,95 * 2 = 99,66 (sq ft)

Answer: 99,66 square feet.