Question #37581

Given 3 points, can one construct a hyperbolic curve thru them using classical geometry of straight edge and compass.

Expert's answer

Answer on Question #37581 - <math> - <geometry>

Given 3 points, can one construct a hyperbolic curve thru them using classical geometry of straight edge and compass.

Solution:

Equation of the hyperbolic curve:


y=kxn+by = \frac {k}{x ^ {n} + b}


If we have three points on the hyperbolic curve (A(x1,y1);B(x2,y2);C(x3,y3))(\mathrm{A}(\mathrm{x}_1,\mathrm{y}_1);\mathrm{B}(\mathrm{x}_2,\mathrm{y}_2);\mathrm{C}(\mathrm{x}_3,\mathrm{y}_3)) , we can substitute the value of XX and YY of every point in the equation (1) and we will have three equations with three unknowns: k,n,bk,n,b . If we will solve the equation and find the unknown variables, it is possible to construct the hyperbolic curve using the equation (1) using known variables k,n,bk,n,b .

Answer: it is possible to construct hyperbolic curve through 3 given points.

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