Question

Angle NOQ~= Angle PQO NO=5x+12 PQ=7x-8 find the length of NO for which NOPQ is a parallelogram

Answer 1

Angle NOQ~ = Angle PQO NO=5x+12 , PQ=7x-8 find the length of NO for which NOPQ is a parallelogram

Solution:

Sides NO and PQ are opposite sides in the parallelogram, so they are equal:

$$N O = P Q$$ $$5 x + 1 2 = 7 x - 8$$ $$2 x = 2 0$$ $$x = 1 0$$

Now we can substitute $X$ in the equation of NO side:

$$N O = 5 x + 1 2 = 5 * 1 0 + 1 2 = 6 2$$

Answer: $NO = 62$