Question #318516

What is the weight of a steel plate 15 feet long, 4 feet wide, and 5/8 inches

Thick, if the steel weighs 475 lbs/ ft3 .

  1. Find the Lateral surface are of the steel plate in square feet.
  2. Compute the Total surface area in square feet.





Expert's answer

For the first convert all units to feet: 5/8 inches is 0.05208 feet.


Volume of the plate is V = length*width*thickness = 15*4*0.05208 = 3.1248 ft3.


Mass of the plate is m = V*density = 3.1248*475 = 14 84.28 lbs.


Lateral surface are of the steel plate is

2*length*thickness+2*width*thickness = 2*15*0.05208+2*4*0.05208 = 1.979 ft2.


Total surface area of the plate is

2*length*width+2*length*thickness+2*width*thickness = 2*15*4+2*15*0.05208+2*4*0.5208 = 121.979 ft2.


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