Answer to Question #309651 in Geometry for Ken

Question

A Region of land 50meters by 40meters is to cross diagonally by a road 15meters wide. What is the roads area?

Answer 1

we start by calculating the value of x

$15^2=x^2+x^2$

$225=2x^2$

$225/2=x^2$

$112.5=x^2$

$\sqrt{112.5}= \sqrt{x^2}$

$10.61=x$

length x= 10.61m

next we find the diagonal D

length = $50-x=50-10.61=39.39$

width =$40-x=40-10.61=29.39$

D=$\sqrt{39.39^2+29.39^2}$

D=$49.15$

area of the road =$15*D$

=$15*49.15$

=$737.25m^2$