Fine the altitude and the area of an equilateral triangle whose side is 60+60+60=180
Explanations & Calculations
h=60sin600=303 at the given unit\qquad\qquad \begin{aligned} \small h&=\small 60\sin60^0\\ &=\small 30\sqrt 3 \,at\,the \,given\,unit \end{aligned}h=60sin600=303atthegivenunit
A=12×base×altitude=0.5×60×303=9003 squared of the given unit\qquad\qquad \begin{aligned} \small A&=\small \frac{1}{2}\times base\times altitude\\ &=\small 0.5\times60\times 30\sqrt3\\ &=\small 900\sqrt3\,\,squared\,of\,the\,given\,unit \end{aligned}A=21×base×altitude=0.5×60×303=9003squaredofthegivenunit
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