Answer to Question #308909 in Geometry for KiTten

Question

Fine the altitude and the area of an equilateral triangle whose side is 60+60+60=180

Answer 1

Explanations & Calculations

• Altitude is (say h),

$\qquad\qquad \begin{aligned} \small h&=\small 60\sin60^0\\ &=\small 30\sqrt 3 \,at\,the \,given\,unit \end{aligned}$

• Area is (say A)

$\qquad\qquad \begin{aligned} \small A&=\small \frac{1}{2}\times base\times altitude\\ &=\small 0.5\times60\times 30\sqrt3\\ &=\small 900\sqrt3\,\,squared\,of\,the\,given\,unit \end{aligned}$