Answer to Question #300158 in Geometry for hiyfcjiiy

Question

,make a circle graph showing the difference school fees that student like you have to pay l. example: PTA , miscellaneous,school paper,SSG and other fees. explane how you applied your knowledge of central angles and arcs of a circle

Answer 1

The different school fees of a typical and ordinary student like me are represented in a circle graph above namely: “School Fees”. Let say that I have Php 5000 budget for different school fees for the whole school year. I spend, Php 2000 for extra-curricular activities in different subject area, Php 1500 for research fund, Php 500 for membership fees of different clubs, Php 200 for photocopy of paper works, and Php 800 for school projects.

a). In the circle graph, what is the measure of the central angle corresponding to each item?

By following the formula: (amount of money per school fees ÷ budget for the

whole school year-Php 5000) x 360

Extra-curricular activities in different subject area

($\frac{2000}{5000}$ ) x 360 = 144°

Research fund

($\frac{1500}{5000}$ ) x 360 = 108°

Membership fees of different clubs

($\frac{500}{5000}$ ) x 360 = 36°

Photocopy of paper works

($\frac{200}{5000}$ ) x 360 = 14°

School projects

($\frac{800}{5000}$ ) x 360 = 58°

b. Suppose the radius of the circle graph is 35 cm. What is the area of each sector in the

circle graph?

Extra-curricular activities in different subject area

$=\dfrac{144\degree}{360\degree}\times\pi\times35^2$ = 1538.6

Research fund

$=\dfrac{108\degree}{360\degree}\times\pi\times35^2$ = 1153.95

Membership fees of different clubs

$=\dfrac{36\degree}{360\degree}\times\pi\times35^2$ = 384.65

Photocopy of paper works

$=\dfrac{14\degree}{360\degree}\times\pi\times35^2$ = 149.58611

School projects

$=\dfrac{58\degree}{360\degree}\times\pi\times35^2$ = 619.71388