Question #29872

Quadrilateral ABCD with vertices A(4, 3), B(4, -2), C(-4, -2) and D(-4, 3) is a rectangle, find the length of the diagonals

Expert's answer

Quadrilateral ABCD with vertices A(4, 3), B(4, -2), C(-4, -2) and D(-4, 3) is a rectangle, find the length of the diagonals.



Diagonals of quadrilateral are AC and BD.

Distance between points with coordinates (x1,y1)(x_{1},y_{1}) and (x2,y2)(x_{2},y_{2}) equals:


d=(x1x2)2+(y1y2)2d = \sqrt {(x _ {1} - x _ {2}) ^ {2} + (y _ {1} - y _ {2}) ^ {2}}


Length of AC equals:


AC=(4(4))2+(3(2))2=64+25=89A C = \sqrt {\left(4 - (- 4)\right) ^ {2} + \left(3 - (- 2)\right) ^ {2}} = \sqrt {6 4 + 2 5} = \sqrt {8 9}


Length of BD equals:


BD=(4(4))2+(3(2))2=64+25=89B D = \sqrt {\left(4 - (- 4)\right) ^ {2} + \left(3 - (- 2)\right) ^ {2}} = \sqrt {6 4 + 2 5} = \sqrt {8 9}


Answer: 89\sqrt{89}

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