Quadrilateral ABCD with vertices A(4, 3), B(4, -2), C(-4, -2) and D(-4, 3) is a rectangle, find the length of the diagonals.
Diagonals of quadrilateral are AC and BD.
Distance between points with coordinates ( x 1 , y 1 ) (x_{1},y_{1}) ( x 1 , y 1 ) and ( x 2 , y 2 ) (x_{2},y_{2}) ( x 2 , y 2 ) equals:
d = ( x 1 − x 2 ) 2 + ( y 1 − y 2 ) 2 d = \sqrt {(x _ {1} - x _ {2}) ^ {2} + (y _ {1} - y _ {2}) ^ {2}} d = ( x 1 − x 2 ) 2 + ( y 1 − y 2 ) 2
Length of AC equals:
A C = ( 4 − ( − 4 ) ) 2 + ( 3 − ( − 2 ) ) 2 = 64 + 25 = 89 A C = \sqrt {\left(4 - (- 4)\right) ^ {2} + \left(3 - (- 2)\right) ^ {2}} = \sqrt {6 4 + 2 5} = \sqrt {8 9} A C = ( 4 − ( − 4 ) ) 2 + ( 3 − ( − 2 ) ) 2 = 64 + 25 = 89
Length of BD equals:
B D = ( 4 − ( − 4 ) ) 2 + ( 3 − ( − 2 ) ) 2 = 64 + 25 = 89 B D = \sqrt {\left(4 - (- 4)\right) ^ {2} + \left(3 - (- 2)\right) ^ {2}} = \sqrt {6 4 + 2 5} = \sqrt {8 9} B D = ( 4 − ( − 4 ) ) 2 + ( 3 − ( − 2 ) ) 2 = 64 + 25 = 89
Answer: 89 \sqrt{89} 89