Answer to Question #295860 in Geometry for Mads

Question

Which rule represents the translation from the pre-image, ABCD, to the image, A'B'C'D'?

T_1, –2(x, y)

T_{1, 2}(x, y)

T_–2, 1(x, y)

T_2, 1(x, y)

Answer 1

T_2, 1(x, y)

Coordinates of the points A,B,C and D of the pre-image ABCD, A(-4, 4), B(-1, 4), C(-5, 1), D(-2,1) Coordinates of the points A', B', C' and D' of the image A'B'C'D'. A'(-2, 5), B'(1, 5), C'(-3, 2), D'(0, 2) Now we choose points A from the pre-image and A' from the image, A(-4, 4) → A'(-2, 5) Rule for the translation will be, A(-4, 4) → A'(-4+2, 4+1) Or A(x, y) → A'(x+2, y+1) Therefore, pre-image ABCD has been shifted 2 units right and 1 unit upwards to form image A'B'C'D'.