Find the lateral area and volume of the frustum of a right circular cone having a slant height of 14m and the radii of the bases are 4m and 1.5 m respectively.
A=π(r1+r2)×lHERE r1=4,r2=1.5,l=14=π(4+1.5)×14π(5.5)×14=241.90m2A=\pi(r1+r2)\times l\\ HERE \, r1=4,r2=1.5,l=14\\=\pi(4+1.5)\times 14\\\pi(5.5)\times 14\\=241.90m^2A=π(r1+r2)×lHEREr1=4,r2=1.5,l=14=π(4+1.5)×14π(5.5)×14=241.90m2
volume
=πH3(r13−r233)=295.08m3=\frac{\pi H}{3}(\frac{r1^3-r2^3}{3})\\=295.08m^3=3πH(3r13−r23)=295.08m3
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