Question #27810

The perimeter of a triangular base of a right prism is 15 cm and radius of the in circle of the triangular base is 3 cm.If the volume of the prism be 270 cubic.Then what will be its height ?

Expert's answer

The perimeter of a triangular base of a right prism is 15cm15\mathrm{cm} and radius of the in circle of the triangular base is 3cm3\mathrm{cm} . If the volume of the prism be 270 (cubic cm) then what will be its height?

Solution:



We have


S=12ra+12rb+12rc=12r(a+b+c)=12315=22,5(cm2)S = \frac {1}{2} r a + \frac {1}{2} r b + \frac {1}{2} r c = \frac {1}{2} r (a + b + c) = \frac {1}{2} \cdot 3 \cdot 1 5 = 2 2, 5 (c m ^ {2})


where SS is the square of the triangular base of the right prism. If hh is the height of the right prism then the volume of one is


V=Sh=270,V = S h = 2 7 0,22,5h=270,2 2, 5 h = 2 7 0,h=12(cm).h = 1 2 (c m).


Answer: h=12(cm)h = 12(cm)

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