The perimeter of a triangular base of a right prism is 15cm and radius of the in circle of the triangular base is 3cm . If the volume of the prism be 270 (cubic cm) then what will be its height?
Solution:

We have
S=21ra+21rb+21rc=21r(a+b+c)=21⋅3⋅15=22,5(cm2)
where S is the square of the triangular base of the right prism. If h is the height of the right prism then the volume of one is
V=Sh=270,22,5h=270,h=12(cm).
Answer: h=12(cm)