Question #26221

if the m<bac=76 degrees, what is the m<boc?
for a circle?

Expert's answer

Question 1.

Let A,B,CA,B,C be points on a circle with center OO. If mBAC=76m\angle BAC=76 degrees, what is mBOCm\angle BOC?

Solution. The angle BAC\angle BAC is inscribed in the circle, and BOC\angle BOC is the central angle that subtends the same arc as BAC\angle BAC. Therefore, the measure of BOC\angle BOC is twice the measure of BAC\angle BAC. Thus,

mBOC=2mBAC=276o=152o.m\angle BOC=2m\angle BAC=2\cdot 76^{\mathrm{o}}=152^{\mathrm{o}}.

Answer: mBOC=152om\angle BOC=152^{\mathrm{o}}. \square

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