Triangle JKL has vertices J (-3, 1), K (-3, -2), and L (1, -2). Rotate ΔJKL 90∘ counterclockwise about the vertex J and write the coordinates of point K after rotation.

Solution:
Move the origin to the point J(-3,1), then the coordinates of the point K (-3,-2) to be
xK′=xK−xJ=−3+3=0yK′=yK−yJ=−2−1=−3K′(0,−3)
Rotate the triangle counterclockwise around the new origin
xK′′=−yK′=3yK′′=xK′=0
Move the origin to its original location
xK∗=xK′′+xJ=3−3=0yK∗=yK′′+yJ=0+1=1
Answer: K∗(0,1)