Question #24965

Triangle JKL has vertices J (-3, 1), K (-3, -2), and L (1, -2). Rotate ΔJKL 900 counterclockwise about the vertex J and write the coordinates of point K after rotation.

Expert's answer

Triangle JKL has vertices J (-3, 1), K (-3, -2), and L (1, -2). Rotate Δ\DeltaJKL 9090{}^{\circ} counterclockwise about the vertex J and write the coordinates of point K after rotation.


Solution:

Move the origin to the point J(-3,1), then the coordinates of the point K (-3,-2) to be


xK=xKxJ=3+3=0x _ {K} ^ {\prime} = x _ {K} - x _ {J} = - 3 + 3 = 0yK=yKyJ=21=3y _ {K} ^ {\prime} = y _ {K} - y _ {J} = - 2 - 1 = - 3K(0,3)\mathrm {K} ^ {\prime} (0, - 3)


Rotate the triangle counterclockwise around the new origin


xK=yK=3x _ {K} ^ {\prime \prime} = - y _ {K} ^ {\prime} = 3yK=xK=0y _ {K} ^ {\prime \prime} = x _ {K} ^ {\prime} = 0


Move the origin to its original location


xK=xK+xJ=33=0x _ {K} ^ {*} = x _ {K} ^ {\prime \prime} + x _ {J} = 3 - 3 = 0yK=yK+yJ=0+1=1y _ {K} ^ {*} = y _ {K} ^ {\prime \prime} + y _ {J} = 0 + 1 = 1


Answer: K(0,1)K^{*}(0,1)

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