ABCD is a right trapezoid (\angle A = 90°), its diagonals intersect at point G. The circle with diameter AB is tangent to lateral side CD of the trapezoid at point H. Find the length of base BC provided that GH = 5, AD = 7.
Since AD=7 cm
and GH=5cm we can see the semi circle in trapezoid whose radius is 5 cm
AB=10cm ( because its the diameter of circle)
since "\\angle A=90\\degree"
and AD is parallel to BC
so "\\angle B=90\\degree"
this show that AD is parallel to BC
AD=7cm so BC=7cm
Comments
Leave a comment