Question

M<PXQ=(8x-3)°,m<PXS=(10x+30)°,find the value of ‘x’ and m<QXS

Answer 1

$10x+30=2(8x-3)$

$10x+30=16x-6$

$16x-10x=30+6$

$6x=36$

$x=6$

$<QXS=<PXQ$

$<QXS=(8×6-3)$

$<QXS=48-3$

$<QXS=45°$